Windsor, Ontario: Manny Pacquiao will fight Shane Mosley, a former champion in three divisions, on May 7 in Las Vegas, promoter Bob Arum said on Tuesday.
The fight, to be held at the MGM Grand, will be contested at the welterweight limit of 147 pounds, Top Rank promoter Arum told Reuters in a telephone interview.
"Mosley is very dangerous, he's a very slick fighter, very experienced," said Arum.
"Manny's style is made to order for Shane. It should be a very, very interesting fight."
After considering a choice between Mosley, lightweight champion Juan Manuel Marquez and WBC welterweight champion Andre Berto, Pacquiao (52-3-2, 38 KOs) informed Arum of his choice last week in the Philippines.
